java : order of execution

Following code and output to illustrate the order of execution of consutrctor, initialization blocks

class InitSuper{
	InitSuper(int x){System.out.println("super: 1-arg const"); }
	InitSuper() { System.out.println("super:no-arg const"); }
	static { System.out.println("super:1st static init"); }
	{ System.out.println("super:1st instance init"); }
	{ System.out.println("super:2nd instance init"); }
	static { System.out.println("super:2nd static init"); }
}

class Init extends InitSuper{
	Init(int x) { System.out.println("1-arg const"); }
	Init() { System.out.println("no-arg const"); }
	static { System.out.println("1st static init"); }
	{ System.out.println("1st instance init"); }
	{ System.out.println("2nd instance init"); }
	static { System.out.println("2nd static init"); }
	public static void main(String [] args) {
		new Init();
		new Init(7);
	}

Output
super:1st static init
super:2nd static init
1st static init
2nd static init
super:1st instance init
super:2nd instance init
super:no-arg const
1st instance init
2nd instance init
no-arg const
super:1st instance init
super:2nd instance init
super:no-arg const
1st instance init
2nd instance init
1-arg const